Question

There are 104 students in class X and 96 students in class IX in a school. In a house examination the students
are to be evenly seated in parallel rows such that no two adjacent rows are of the same class.
i) Find the maximum number of parallel rows of each class for the seating arrangement.
ii) Also find the number of students of class IX and also of class X in a row.
iii) What is the objective of the school administration behind such an arrangement.

Answer 1

Answer:

Step-by-step explanation:

There are a total of 200 students (104 and 96).

Both 104 and 96 are divisible by 8, i.e. 104/8 = 13 and 96/8 = 12.

a). Therefore the maximum number of parallel rows would be 12+13 = 25. And, 200/8 = 25.

b). Number of students in each row would be 8.

c). The objective of the school behind such an agreement would be to easily arrange the students in rows such that no adjacent rows have students belonging to one class.