Question

There are (10a +13b) passengers on a train. If (4a -3b) and (5b-2a) passengers board at
two consecutive stations, what is the number of passengers on the train now?​

Answer 1

total number of passengers=10a+13b

4a-3b and 5b-2a board at two consecutive stations

so, (4a-3b)+(5b-2a)=2a+2b

∴no. of passengers in train now=(10a+13b)+(2a+2b)

                                                    =12a+15b

Answer 2

Answer:

Passenger on a train = (5b-13b)

passenger board at first stations = (4a-2a)

passenger board at second stations = (5b-2a)

first we will find total passenger board at both stations = (4a-3b)+(5b-2a)

=(2a+2b)

number of passengers on the train now

= (10a+13b)+(2a+2b)

=(12a+15b)