Question

There are 10a + 5b passengers on a train. If (-4a - 2b) and (6b - 2) board at
two consecutive stations respectively, what is the number of passengers in the
train now?
​

Answer 1

Answer:

10a+5b-(-4a-2b)+(6b-2)

10a+5b+4a+2b+6b-2

(10+4)a+(5+6)b-2

14a+11b-2

Hope it may help you!!

Step-by-step explanation:

please mark me as brainliest

Answer 2

Answer:

Passenger on a train = (5b-5b)

passenger board at first stations = (-4a-2a)

passenger board at second stations = (6b-2)

first we will find total passenger board at both stations = (-4a-2b)+(6b-2)

=(-4a+4b-2)

number of passengers on the train now

= (10a+13b)+(-4a+4b-2)

=(6a+17b-2)