Question

There are 12 cylindrical pillars, each of diameter 56 cm and height 440 cm in a hall. Find the cost of painting the pillars at the rate of rs 50 per sq. m.​

Answer 1

Answer:

Rs 46464

Step-by-step explanation:

number of cylinders = 12

diameter of the cylinder = 56

radius = 28

height of the cylinder = 440

formula of the curved surface area of a cylinder = 2π r × h

2 × 22/7 × 0.28 × 44

44/7 × 0.28 × 44

12.32/7 × 44

= 77.44 m²

77.44 × 50 = rs 3872

3872 × 12 = rs 46464

= Rs 46464

Answer 2

Answer:

$\huge\colorbox{yellow}{Given\:-}$

• No. of cylindrical pillars = 12

• Diameter = 56 cm

• Height = 440 cm

$\huge\colorbox{yellow}{To\:Find\:-}$

The cost of painting of pillars at ₹50 per sq. m

$\huge\colorbox{yellow}{Solution\:-}$

$Radius = \frac{56}{2} = 25 \: cm$

$\boxed{CSA\:of\:Cylinder = 2\pi \: rh}$

Now,

$2 \times \frac{22}{7} \times 28 \times 440$

$= 44 \times 1760$

$= 77440 \: {cm}^{2}$

One pillar = 77440

$12 \: pillars =77440 \times 12$

$= 939280 \: {cm}^{2}$

$= \frac{939280}{100 \times 100} \: {m}^{2}$

$= 93.9280 \: {m}^{2}$

Cost of painting of pillars at ₹ 50 per m2

$93.928 \times 50$

$\boxed{\pink{ = > 4646.4}}$

The cost of painting is ₹ 4646.4 m2

$\huge\colorbox{yellow}{Thank\:You}$