there are 120 boys and 114 girls distributed in claases in rqual no. What is max no. of such sections
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Answered by
58
Hey Friend !
Total No: of boys = 120
Total No: of Girls = 114
Girls and Boys are distributed in different classes each with equal no: of boys and girls.
To find , about which is the maximum no: of classes required to accommodate the students with equal no: of boys and girls , we have to find the HCF of 120 and 114.
120 > 114
120 = 114 × 1 + 6
114 = 6 × 19 + 0
HCF = 6
Hence , the maximum no: of classes , where there are equal no: of girls and boys are 6 .
Total No: of boys = 120
Total No: of Girls = 114
Girls and Boys are distributed in different classes each with equal no: of boys and girls.
To find , about which is the maximum no: of classes required to accommodate the students with equal no: of boys and girls , we have to find the HCF of 120 and 114.
120 > 114
120 = 114 × 1 + 6
114 = 6 × 19 + 0
HCF = 6
Hence , the maximum no: of classes , where there are equal no: of girls and boys are 6 .
Answered by
11
Answer:
Step-by-step explanation:
Girls and Boys are distributed in different classes each with equal no: of boys and girls.
To find , about which is the maximum no: of classes required to accommodate the students with equal no: of boys and girls , we have to find the HCF of 120 and 114.
120 > 114
120 = 114 × 1 + 6
114 = 6 × 19 + 0
HCF = 6
Hence , the maximum no: of classes , where there are equal no: of girls and boys are 6
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