Math, asked by rekhasingh5479, 1 day ago

there are 1250 children in a school. for a PT drill they have to stand in such in such a way that number of rows is equal to number of columns .how many children are left out of the arrangement​

Answers

Answered by laxitasodhani
8

Answer:

Number of children left out are 25.

Step-by-step explanation:

Total number of children in the school = 1250 children

Let the number of rows the children stand in = x rows

According to question, number of rows = number of columns

Hence, Number of columns = x columns

If we have an arrangement of x rows and x columns,

The total children that can fit in = x^2

x^2 <= 1250

(we need to find the highest perfect square less than or equal to 1250)

x <= 35.35

(by using long division method to find square root of 1250)

(x is strictly an integer, rows cant be decimal values)

the nearest smaller integer = 35

x^2 = (35)^2

= 1225

Hence, 1225 children can stand in an arrangement of x rows and x columns.

Children left out = total children - children that can be arranged

                            = 1250 - 1225

                             = 25 children

Answered by Swarup1998
0

25 children are left out of the arrangement.

Step-by-step explanation:

Tip. Since the children have to stand in such a way that the number of rows is equal to the number of columns, we find the square root of 1250.

Prime factorization gives 1250 = 2 × 5 × 5 × 5 × 5

So, √1250 = 5 × 5 × √2 = 25√2 = 35.35...

Thus the number of required rows = the number of required columns = 35

Now, the number of children required for the PT drill

= 35 × 35 (or, 35²)

= 1225

So, the number of children left out

= 1250 - 1225

= 25

#SPJ3

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