Question

there are 13 triangles with one leg is 1729 in Pythagorean triangles.another leg is 672. now the third leg is

Answer 1

Solution :-

It is assumed that the length of hypotenuse is to be find out in this question.

According to the Pythagoras Theorem 

(Hypotenuse)² = (Base)² + (Perpendicular)²

(H)² = (1729)² +(672)² 

(H)² = 2989441 + 451584

(H)² = 3441025

(H)² = √3441025

Hypotenuse = 1855

So, the length of third leg is 1855 unit.

Answer 2

In this question we assumed that the length of hypotenuse of a Pythagorean ∆ is to be find.

Given :

Base of Pythagorean ∆ = 1729

Perpendicular of Pythagorean ∆ = 672

According to the Pythagoras Theorem .

Hypotenuse² = Base² + Perpendicular²

H²= (1729)² +(672)²

H²= 2989441 + 451584

H² = 3441025

H= √3441025

Hypotenuse = 1855


Hence, the length of third leg of Pythagorean ∆ is 1855 unit

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Hope this will help you......