Math, asked by sathijana393, 3 months ago

there are 15 balls of three different colours in a bag. Out of them 4 are yellow, 6 are green and 5 are black. find: I) the probability of drawing a green ball.
2) the probability of drawing a black or a yellow ball. ​

Answers

Answered by mashisaini646
2

ans.

ans.All possible case in drawing 3 balls from 12

ans.All possible case in drawing 3 balls from 12 12

ans.All possible case in drawing 3 balls from 12 12 C

ans.All possible case in drawing 3 balls from 12 12 C 3

ans.All possible case in drawing 3 balls from 12 12 C 3

ans.All possible case in drawing 3 balls from 12 12 C 3 =

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 ×

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 =

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! ×

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7!

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70Hence the required probability =

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70Hence the required probability = 220

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70Hence the required probability = 22070

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70Hence the required probability = 22070

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70Hence the required probability = 22070 =

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70Hence the required probability = 22070 = 22

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70Hence the required probability = 22070 = 227

ans.All possible case in drawing 3 balls from 12 12 C 3 = 3!9!12! =220Fovourable cases to draw exactly 2 red wall 5 C 2 × 7 C 1 = 2!3!5! × 1!6!7! =70Hence the required probability = 22070 = 227

Similar questions