There are 15 cards on the table marked from 0 to 14. What is the probability of getting a card with: i)An even number. ii)A prime number iii) Not a multiple of 3. iv)The number 15.
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(i) Even Numbers are 0,2,4,6,8,10,12 and 14 i.e there are 8 even numbers
Probability= 8/15
(ii) Prime numbers are 2,3,5,7,11 and 13 i.e there are 6 prime numbers.
Probability= 6/15= 2/5
(iii) Multiples of 3 are 0,3,6,9 and 12 i.e there are 5 prime numbers.
Probability=5/15= 1/3
(iv) There is no number 15 i.e probability is 0/15 = 0
Probability= 8/15
(ii) Prime numbers are 2,3,5,7,11 and 13 i.e there are 6 prime numbers.
Probability= 6/15= 2/5
(iii) Multiples of 3 are 0,3,6,9 and 12 i.e there are 5 prime numbers.
Probability=5/15= 1/3
(iv) There is no number 15 i.e probability is 0/15 = 0
jordan13:
they have told that not o multiple of three so read the question
Oh.... Very sorry.... Should be 2/3
no problem
no 0 is not a multiple of 3
Answered by
1
first P(E) =8/15
second P(E)= 6/15
third P(E)= 11/15
fourth P(E)= 0/15
second P(E)= 6/15
third P(E)= 11/15
fourth P(E)= 0/15
Yes you are correct.
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