Question

there are 15 tickets bearing the number 1 to 15 in a bag .one ticket is drawn at random from the bag . to find the probability of event A that the ticket drawn bears multiple of 5 , fill in the box

Answer 1

Answer:3/15=1/5

Step-by-step explanation:

Answer 2

Given:

15 tickets bearing the number 1 to 15 in a bag.

To Find:

the probability of event A that the ticket drawn bears a multiple of 5.

Solution:

It is given that there are 15 tickets bearing the number 1 to 15 in a bag

So, the sample space will be,

S= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 }

n(S) = 15

Event A is the ticket drawn that bears a multiple of 5.

A ={ 5, 10, 15}

n(A) = 3

Probability of A = No. of Favourable events/ total no. of events

P(A)= n(A)/n(S)

= 3/15

= 1/5

Hence, the probability of event A that the ticket drawn bears a multiple of 5 is 1/5.