Math, asked by rashmi4113, 10 months ago

There are 15000 people watching a football match in a studium and one-third of the chair are unoccupied. What is the capacity of the stadium?

Answers

Answered by Steph0303
80

Answer:

Given that 15,000 people are watching he match.

Also it is stated that 1/3 rd of the stadium is unoccupied.

This means that 2/3 rd of the stadium is occupied. Also we know the value of people occupying the 2/3 rd of seats which is 15,000 according to the question.

Therefore Let us assume the total number of seats in stadium to be 'x'

⇒ ( 2/3 ) × x = 15,000

⇒ x = 15,000 × 3/2

⇒ x = 45,000/2

x = 22,500

Therefore the total capacity of the stadium is 22,500 seats.

Answered by smithasijotsl
0

Answer:

Total capacity of the stadium = 22500

Step-by-step explanation:

Given,

Total number of people watching the football match = 15000

The fraction of the chair unoccupied = \frac{1}{3}

To find,

The capacity of the stadium

Solution:

Let 'x' be the total capacity of the stadium

Since the fraction of the chair unoccupied = \frac{1}{3}, the fraction of the chair occupied = 1 - \frac{1}{3} =  \frac{2}{3}

Since the total capacity of the stadium is 'x', then the number of chair occupied =  \frac{2}{3}x

Since it is given that the number of people watching the match = 15000, we have

\frac{2}{3}x =  15000

x = 7500×3

= 22500

x = 22500

Total capacity of the stadium = 22500

#SPJ2

Answered by smithasijotsl
0

Answer:

Total capacity of the stadium = 22500

Step-by-step explanation:

Given,

Total number of people watching the football match = 15000

The fraction of the chair unoccupied = \frac{1}{3}

To find,

The capacity of the stadium

Solution:

Let 'x' be the total capacity of the stadium

Since the fraction of the chair unoccupied = \frac{1}{3}, the fraction of the chair occupied = 1 - \frac{1}{3} =  \frac{2}{3}

Since the total capacity of the stadium is 'x', then the number of chair occupied =  \frac{2}{3}x

Since it is given that the number of people watching the match = 15000, we have

\frac{2}{3}x =  15000

x = 7500×3

= 22500

x = 22500

Total capacity of the stadium = 22500

#SPJ2

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