Question

There are 16 red and 12 blue containers on a shelf. If 5 containers are selected at random then what is probability that 3 of them will be red and 2 will be blue

Answer 1

Answer:

THE PROBABILITY OF RED COLOUR IS 3/16

THE PROBABILITY OF BLUE COLOUR IS 2/12 = 1/6

Step-by-step explanation:

THE PROBABILITY OF RED COLOUR IS 3/16

THE PROBABILITY OF BLUE COLOUR IS 2/12 = 1/6

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Answer 2

Given,

• Number of red containers = 16
• Number of blue containers = 12

To find,

• Probability if 5 containers are selected at random then 3 of them will be red and 2 will be blue.

Solution,

The probability that if 5 containers are selected at random then 3 of them will be red and 2 will be blue 44/117.

Total number of balls = 28

Total number of cases  = $^{28} C_{5}$

Number of cases of getting 3 red balls and 2 blue balls = $^{16}C_{3} * ^{12}C_{2}$

Probability = favorable cases/ Total number of cases

                  =  $^{16}C_{3} * ^{12}C_{2}$ / $^{28} C_{5}$

                  = 36960/98280

                  =  44/117

∴ The required probability is 44/117.

The probability that if 5 containers are selected at random then 3 of them will be red and 2 will be blue 44/117.