Question

There are 17 balls, numbered 1 to 1 7 in a bag. If a person selects one ball at
random. what is the probability that the number printed on the ball will be an
even number greater than 9 ?​

Answer 1

Answer:

numbers greater than 9 are 10,11,12,13,14,15,16,17

probability=8/17

please mark it as brainliest ❤️❤️

Answer 2

Answer:

The probability that the number printed on the ball will be an even number greater than 9 =  $\frac{4}{17}$

Step-by-step explanation:

Given

In a bag, there are 17 balls numbered 1 to 17

To find,

The probability that the number printed on the ball will an even number greater than 9.

Recall the formula

Probability = $\frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes}$

Solution:

Since the balls are numbered 1 to 17, the total outcomes are

{1,2,3,...................17}

Total number of outcomes  = 17

The possible outcomes of getting an even number greater than 9 = {10,12,14,16}

Number of possible outcomes of getting an even number greater than 9 = 4

∴The probability of getting an even number greater than 9

=  $\frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes}$

= $\frac{4}{17}$

The probability that the number printed on the ball will be an even number greater than 9 =  $\frac{4}{17}$

#SPJ2