Math, asked by vidhu18, 1 year ago

There are 18 guests in a dinner party. They have to sit 9 guests on either side of a long table,three particular persons decide to sit on one side and two others on the other side.In how many ways can the guests to be seated?​

Answers

Answered by byrdjoseph13811
1

Answer:

Four particular guests desire to sit on one particular side and three others on ... guests out of which we choose 5 for side A in ways and remaining 6 for other ... Hence, the number of selection for two sides is . Now 9 persons on each side of the table can be arranged among themselves in 9! ... You have rated this answer /10.

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