Question

There are 20 rows of seats of a concert hall: 25 seats are in the 1st row, 27 seats on the 2nd row, 29 seats on the 3rd row, and so on. If the price per ticket is Aed 50, how much will be the total sales for a one-night concert if all seats are sold.

Answer 1

Answer:

44000 will be the sales of the old night concert

Answer 2

The total sales for a one-night concert if all seats are sold is Rs.44000

Step-by-step explanation:

No. of seats in First row = 25

No. of rows in second row = 27

No. of rows in third row = 29

and so on

So, It forms AP

AP : 25,27,29,....

There are 20 rows of seats of a concert hall

So, n = 20

a = first term = 25

d = common difference = 27-25=29-27 = 2

Sum of first n terms =$S_n=\frac{n}{2}(2a+(n-1)d)$

So, total no. of seats in hall = $S_{20}=\frac{20}{2}(2(25)+(20-1)2)=880$

Price of 1 ticket = Rs.50

Price of 880 tickets = $880 \times 50 = 44000$

Hence  the total sales for a one-night concert if all seats are sold is Rs.44000

#Learn more :

The sum of first five terms of an AP and the sum of first seven terms of the same AP is 167. If the sum of first 10 terms of this AP is 235. Find the sum of first 20 terms

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