Question

there are 2310 students in a school for a special assembly they need to stand in such a manner that the number of rows is equals to number of columns how many students would be left out of this arrangement​

Answer 1

GIVEN:

Total. No of students=2310

And no.of rows is equal to no.of columns.

SOLUTION:

Let no.of rows = x

and also no.of columns=x

NOW,

Total no.of.students= no.of rows x no.of columns

2310 = x*x

2310 = x²

x²= 2310

x= √2310

x= 48.06

x= 48

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Answer 2

Answer:

48

Step-by-step explanation:

${48}^{2} = 2304 \\ 2310 - 2304 = 6 \\ hence \: student \: will \: be \: arranged \: 48 \: by \: 48 \\ \: and \: 6 \: students \: left \: behind$