Question

how much work is done in moving a charge of 28C from a point 318V to 480V?​

Answer 1

Answer:

volts is 50 J.

Explanation:-

We know that potential difference = Work done/Charge moved.

We know that potential difference = Work done/Charge moved.In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.

We know that potential difference = Work done/Charge moved.In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.Thus, the potential difference = v2-V1 = 230-240 = 10 V

We know that potential difference = Work done/Charge moved.In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.Thus, the potential difference = v2-V1 = 230-240 = 10 VTherefore, Work done = Potential difference * Charge moved.

We know that potential difference = Work done/Charge moved.In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.Thus, the potential difference = v2-V1 = 230-240 = 10 VTherefore, Work done = Potential difference * Charge moved.That is, 10 * 5 = 50 Joules.

We know that potential difference = Work done/Charge moved.In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.Thus, the potential difference = v2-V1 = 230-240 = 10 VTherefore, Work done = Potential difference * Charge moved.That is, 10 * 5 = 50 Joules.Hence, the work done in moving a charge of 5 coulombs from a point at 230 volts to another point at 240 volts is 50 J.

Hope This helps you mate

#Siddharth here!