Question

There are 24 balls in a pot. If 3 of them are Red, 5 of them are Blue and the remaining are Green then, what is the probability of picking out.a Blue ball. a Red ball and, a Green ball

Answer 1

probability of blue Ball= 5/24

probability of red ball=3/24

=1/8

probability of green ball =16/24

1/3

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Answer 2

Answer:

Step-by-step explanation:

Total No. of Balls ⇒ 24

No. of Red Balls ⇒ 3

No. of Blue Balls ⇒ 5

Then,

No. of Green Balls ⇒ 5 + 3 = 8

⇒ 24 - 8 = 16

∴ No. of Green Balls ⇒ 16

Probability of picking out

a Blue ball ⇒ $\frac{5}{24}$

a Red ball ⇒ $\frac{3}{24}$

a Green ball ⇒ $\frac{16}{24} = \frac{2}{3}$