Question

There are 240 coconuts trees in a groove and 60% of them are fertile. How many are infertile

Answer 1

Total number of coconuts=240

Let the number of infertile coconuts be x.

Fertile coconuts = 60/100*240= 6*24= 144

Therefore, 144+X =240

x = 240-144

= 96

There are 96 infertile coconuts.