There are 240 coconuts trees in a groove and 60% of them are fertile. How many are infertile
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Total number of coconuts=240
Let the number of infertile coconuts be x.
Fertile coconuts = 60/100*240= 6*24= 144
Therefore, 144+X =240
x = 240-144
= 96
There are 96 infertile coconuts.
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