Question

There are 25 counters with numbers ranging from 2 to 26. If one counter is picked at random, calculate the probability that it is divisible by both 2 and 5.

Answer 1

Answer:

बर्गर थर्ड. ठदददठ ज्ञठदददठ थर्ड थठरज्ञठथक्षठदठज्ञद दठज्ञर थडरक्ष द

झफधधठ

विधवा

विविध

धखनखन

ख़धखध

Answer 2

Answer:

Step-by-step explanation:

Let S be the sample space i.e bag contains cards numbered from 1 to 25.

Let S be the sample space i.e bag contains cards numbered from 1 to 25.n(S) = 25 .

Let S be the sample space i.e bag contains cards numbered from 1 to 25.n(S) = 25 .A event of getting the number on this card is divisible by both 2 and 3 is n(A)

Let S be the sample space i.e bag contains cards numbered from 1 to 25.n(S) = 25 .A event of getting the number on this card is divisible by both 2 and 3 is n(A)= { 6,12,18,24} = 4

Let S be the sample space i.e bag contains cards numbered from 1 to 25.n(S) = 25 .A event of getting the number on this card is divisible by both 2 and 3 is n(A)= { 6,12,18,24} = 4P(A) = 4 over 25

Let S be the sample space i.e bag contains cards numbered from 1 to 25.n(S) = 25 .A event of getting the number on this card is divisible by both 2 and 3 is n(A)= { 6,12,18,24} = 4P(A) = 4 over 25(ii)number of prime number between 1 to 25 =9

Let S be the sample space i.e bag contains cards numbered from 1 to 25.n(S) = 25 .A event of getting the number on this card is divisible by both 2 and 3 is n(A)= { 6,12,18,24} = 4P(A) = 4 over 25(ii)number of prime number between 1 to 25 =9hence probability =9 over 25

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