Question

There are 258 g of MgCl2/liters. What is the molarity of the solution?

Answer 1

$\huge\underline\orange{\mathcal Answer}$

$\large\blue{\boxed{\mathcal Molarity=2.7M}}$

$\huge\underline\orange{\mathcal Solution}$

Given :-

mass = 258 g

molar mass = 95.2 g/mol

molarity = ?

$\huge\boxed{\mathcal Molarity={\frac{Mole}{Litre}}}$

$\large{\mathcal Mole (n)={\frac{Mass}{Molar\:Mass}}}$

$\large{\mathcal n={\frac{258}{95.2}}}$

$\large{\mathcal n=2.7}$

$\large{\mathcal Molarity={\frac{2.7}{1}}}$

$\huge\boxed{\mathcal Molarity=2.7M}$

$\huge\orange{\mathcal Hope\:It\:Helps!!!}$

Answer 2

The Molarity of the solution is 2.7 M.

Explanation:

The molarity of the solution is defined as number of moles of the solute dissolved in the given volume.

Data given:

mass of MgCl2 is 258 grams, volume is 1 litre.

and molar mass of MgCl2 is known by adding atomic eight of one mole of Mg and adding the molecular weight of chlorine diatom. 24+70.906

Molar mass of MgCl2= 95.211 gram/mole

number of moles is calculated by the formula:

number of moles (n) = $\frac{mass}{atomic mass of one mole}$

n = $\frac{258}{95.211}$

  =2.709  moles of MgCl2 is there.

molarity is calculated by the formula:

molarity (M) = $\frac{number of moles}{volume in litres}$

M = $\frac{2.709}{1}$

The molarity of the 258 grams of MgCl2 in 1 litre of solvent is 2.709 M

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