There are 260, 208 and 156 students in the classes, VI, VII and VIII respectively. Buses are to be hired to take these students to the National Museum. Find the maximum number of students who can sit in the bus if each bus takes an equal number if students. Find the number of buses required.
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You should take H.C.F. of 156, 208 and 260.
=> HCF of 156 and 208
P.F. of 156 = 2×2×3×13
P.F. of 208 = 2×2×2×2×13
Therefore, H.C.F. of 156 and 208 = 2×2×13 = 52
=> Now , H.C.F. of 52 and 260
P.F. of 52 = 2×2×13
P.F. of 260 = 2×2×5×13
H.C.F. = 2×2×13 = 52
●Max. number of students per bus = 52
●Total number of students = 156+208+260 = 624 students.
●No. of buses = 624/52 = 12 buses.
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