Question

there are 2601 students in a school. during assembly time , the students stand in such a way that the number of students in each row is equal to the number of rows . how many students stand in each row?

Answer 1

students standing in row = root 2601
$\sqrt{2601 } = 51$
therefore no of students = 51
no of rows = 51


please mark it as brainlist

Answer 2

Answer:

Concept:

• Prime factorization is the technique of expressing a number as the product of prime numbers.
• One and the number itself are the only two factors in prime numbers.
• Prime numbers include, for instance, $2, 3, 5, 7, 11, 13, 17, 19,$ and so on.
• To represent a number as a composite of prime numbers is to prime factorize it.
• The process of breaking down a composite number into smaller integers is known as integer factorization.

Given:

• Total number of students during assembly time $= 2601$
• The number of students in each row is equal to the number of rows.

To Find:

We need to find how many students stand in each row.

Solution:

Total number of students during assembly time is $2601$.

Number of rows is equal to the  number of students in each row (i.e., number of columns)

Number of row $=$ Number of students in each row

Let $x$ be the number of rows. Number of column is also $x$, since it is equal to number of rows.

Total students in assembly $= x*x$

⇒  $x*x=2601$

⇒  $x^{2} = 2601$

⇒  $x= \sqrt{2601}$

Let's use prime factorization to solve this,

⇒  $x= \sqrt{17*17*3*3}$

⇒  $x= \sqrt{17^{2} *3^{2} }$

⇒  $x = 17* 3$

⇒  $x = 51$

Number of rows is $51$.

Since, number of rows is equal to the  number of students in each row.

Then, number of students in each row is $51$.

∴ Number of students in each row is $51$.

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