Question

There are 27 drops of a conducting fluids. Each has a radius r and they are charged to a potential v0. These are combined to form a bigger drops. It's potential will be:

Answer 1

Answer:

Explanation:let r be the radius of each small drop..and R be the radius of bigger drop.

Total vol of 27 droplets = vol of bigger drop.

27×(4/3)×π×r^3=(4/3)×π×R^3

R=3r

Let charge on each sphere is q.

Potential due to each sphere is v not =Kq/r

The total charge on bigger drop is 27q

Hence potential due to this bigger drop is V=(K×27×q)/R

V=(27×k×q)/3r

V=9×(Kq/r)

V=9v not.

Answer 2

Answer:

hope it helps

Explanation:

9Vo. .........