CBSE BOARD XII, asked by shalurajput8223, 7 months ago

There are 28 teams in a knockout tournament fixture, What is total number of byes ? Write in double digit numbers like 01,10 etc.

Answers

Answered by kaushallegend2005
0

Answer:

4

Explanation:

In the 1st round the number of teams playing would be

28/2 = 14

In the 2nd round it will be

14/2 = 7

In the 3rd round it will be

7+1/2 = 4. As no. of teams are odd

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Answered by Dhruv4886
0

The total number of byes is 04.

Given:

There are 28 teams in a knockout tournament fixture

To find:

What is the total number of byes? Write in double-digit numbers like 01, 10, etc.  

Solution:

In knockout tournaments, in each match, there will be two competitors and only one team can advance to the next round.

To determine the number of byes, we need to find the smallest power of 2 that is greater than or equal to 28.

In this case, that would be 32. So we have 32 slots in the first round, but only 28 teams. That means there will be 32-28 = 4 byes.

The byes are given to the teams that would have been matched up with the 4 extra slots.

Specifically, the teams in positions 29, 30, 31, and 32 will get the byes.

So the total number of byes is 4, and we can represent this as "04" in double-digit format.  

Therefore,

The total number of byes is 04.

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