Question

There are 2n consecutive natural numbers. if n + 1 numbers are randomly selected, then what is the probability that their hcf is 1?

Answer 1

Answer:

The probability for n + 1 numbers that are randomly selected from 2n consecutive natural numbers such that their HCF is 1 will be zero/0.

Given: Consecutive Natural numbers - 2n (2, 4, 6, 8..............2n)

where n =(1, 2, 3, ...........n)

Step-by-step explanation:

Probability = Desired Output / Total Output

Since 2 even numbers will not have HCF or highest common factor as 1 because their HCF will always be 2.

Therefore the probability that their HCF is 1 will always o.

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