There are 5 letters and five addressed envelopes. the number of ways in which all the letters can be put in wrong envelopes is
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Answered by
20
SO
we can solve this problem by using method of dearrangement
=5![1-(1/1!)+(1/2!)-(1/3!)+(1/4!)+1/5!]
=the answer is
=44
we can solve this problem by using method of dearrangement
=5![1-(1/1!)+(1/2!)-(1/3!)+(1/4!)+1/5!]
=the answer is
=44
Answered by
20
Answer:
44 ways
Step-by-step explanation:
There are 5 letters and five addressed envelopes. the number of ways in which all the letters can be put in wrong envelopes is
Total Number of ways = 5! = 120
The formula for the derangement can be used directly. The number of derangements is
n! (1/2!−1/3!+1/4!+…+(−1)ⁿ/n!)
Here n = 5
5 ! ( 1/2! - 1/3! + 1/4! - 1/5!)
= 120 ( 1/2 - 1/6 + 1/24 - 1/120)
= 60 - 20 + 5 - 1
= 65 - 21
= 44
44 ways in which all the letters can be put in wrong envelopes
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