Math, asked by Karanbhutna5076, 1 year ago

There are 5 letters and five addressed envelopes. the number of ways in which all the letters can be put in wrong envelopes is

Answers

Answered by Saisurya
20
SO 
we can solve this problem by using method of dearrangement 

=5![1-(1/1!)+(1/2!)-(1/3!)+(1/4!)+1/5!]
=the answer is 
=44
Answered by amitnrw
20

Answer:

44 ways

Step-by-step explanation:

There are 5 letters and five addressed envelopes. the number of ways in which all the letters can be put in wrong envelopes is

Total Number of ways = 5! = 120

The formula for the derangement can be used directly. The number of derangements is

n! (1/2!−1/3!+1/4!+…+(−1)ⁿ/n!)

Here n = 5

5 ! ( 1/2!  -  1/3!  + 1/4!   - 1/5!)

= 120 ( 1/2 - 1/6  + 1/24 - 1/120)

= 60 - 20 + 5 - 1

= 65 - 21

= 44

44 ways in which all the letters can be put in wrong envelopes

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