There are 5 letters and five addressed envelopes. the number of ways in which all the letters can be put in wrong envelopes is
Answers
Answered by
20
SO
we can solve this problem by using method of dearrangement
=5![1-(1/1!)+(1/2!)-(1/3!)+(1/4!)+1/5!]
=the answer is
=44
we can solve this problem by using method of dearrangement
=5![1-(1/1!)+(1/2!)-(1/3!)+(1/4!)+1/5!]
=the answer is
=44
Answered by
20
Answer:
44 ways
Step-by-step explanation:
There are 5 letters and five addressed envelopes. the number of ways in which all the letters can be put in wrong envelopes is
Total Number of ways = 5! = 120
The formula for the derangement can be used directly. The number of derangements is
n! (1/2!−1/3!+1/4!+…+(−1)ⁿ/n!)
Here n = 5
5 ! ( 1/2! - 1/3! + 1/4! - 1/5!)
= 120 ( 1/2 - 1/6 + 1/24 - 1/120)
= 60 - 20 + 5 - 1
= 65 - 21
= 44
44 ways in which all the letters can be put in wrong envelopes
Similar questions