There are 3 consecutive even integers that have a sum of 210.
Answers
Answered by
7
Now, let's come to the question :-
Let the three consecutive even numbers be x , x + 2 and x + 4
A/q,
x + x + 2 + x + 4 = 210
3x + 6 = 210
3x = 210 - 6
3x = 204
x =
x = 68
1st consecutive number => x => 68
2nd consecutive number => x + 2 => 68 + 2 => 70
3rd consecutive number => x + 4 => 68 + 4 => 72
The three consecutive even numbers are 68, 70 and 72
Answered by
18
_________________________
Sum of 3 consecutive even numbers = 210
_________________________
Let the first consecutive even number be x
Second consecutive even number
= x + 2
Third consecutive even number = x + 4
_________________________
x + x + 2 + x + 4 = 210
=> 3x + 6 = 210
=> 3x = 210 - 6
=> 3x = 204
=> x = 204/3
=> x = 68
________________________
The numbers are :
● 68
● 70
● 72
_________________________
#BE BRAINLY
@Sanskriti141
Similar questions