Question

there are 3 consecutive positive integer such that the sum of the first and the product of the other two is 191.what are the two integers​

Answer 1

Answer:

9,10,11

Correction inquestion:

there are 3 consecutive positive integer such that the sum of the square of first and the product of the other two is 191.what are the two integers​

Step-by-step explanation:

let no are x-1,x,x+1

(x-1)^2+x(x+1)=191

x2-2x+1+x2+x-191=0

2x2-x-190=0

x=1±√1+1520/4

=1±39/4

=1+39/4

=40/4=10

so the numbers are

9,10,11