Question

there are 3 consecutive positive integers such that the sum of the square of the first and the product of the other two is 154 we would like to find out the smallest positive integer

Answer 1

let the no are x , x+1 and x+2
then
x^2 + (x+1 ) (x+2) = 154
= 2x^2 + 3x +2 = 154
= 2x^2 +3x = 152
= 2x^2 +3x - 152 = 0
= 2x^2 +19x - 16x - 152 =0
=x (2x+19) -8 (2x +19)
=(x- 8) ( 2x +19) = 0
there are two values
1 - x-8 = 0 2- 2x + 19 = 0
x = 8 x = -19/2
but the question clearly said that integer is positive
so
x = 8
x+ 1 = 9
x+2 =10

Answer 2

Answer:

.here is the correct answer... mark as brainiest