Math, asked by scott4693, 1 year ago

there are 3 trains named a b c which go from karachi to lahore and leave from karachi at same time. the distance between karachi and lahore is 1500 kms. when train a reached lahore train b was 150 km away from destination. when train b reached lahore train c was 150 km away from destination.


biradarshruti11: The following equations are in different number system other than base 10 find value is x in decimal (base 10). 50-41=6 and 55-36=X

Answers

Answered by imhkp4u
0

Though the question isn't complete as it is not mentioned what to evaluate, we'll compute the time taken by the three trains A, B and C.

For Train A:

Distance = 1500km.

Time = t

Speed = s km/h

t = 1500/s hours


For Train B:

Distance = (1500 - 150)km = 1350km

Time = t Speed = 1350/t km/h

Therefore, time taken for 1500 km will be

= (1500 / (1350/t)) = (1500t/1350)

or, 10t/9 hours


For Train C:

Distance = 1350km.

Time = 10t/9 hours

Speed = 1350/(10t/9) = 1215/t km/h

Time for 1500 km will be = (1500 / (1215/t)) = 1500t/1215 = 100t/81 hours.

Thus the conclusion stands:

Train B takes 10/9 times and Train C takes 100/81 times more time than that of Train A.

Answered by mithulrajkumar
0

Answer:

Step-by-step explanation:

This is testing on relative distance.

The relative distance between a and b is :

= 150 km

The relative distance between b and c is :

= 150 km

The relative distance between a and c is :

150 + 150 = 300 km

C was 300 km away from Lahore when A reached Lahore

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