There are 3 yellow balls and 5 red balls in a bag. What is the probability of drawing out blue ball
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p(drawing of blue ball)=0/7 mark me as brainliest
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The probability of one ball being red and one ball being yellow is the number of ways of choosing one red and 1 yellow divided by the number of ways of drawing 2 balls overall. There are 3 red, and there are 2 yellow, and there are 10 balls overall, so that gives us:
(31)(21)(102)=645=215=0.13¯¯¯
The overline above the 3 represents that the 3 is a repeating digit.
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