There are 30 cards numbered froml to 30. One card is drawn at random. Find the probability of
getting the card with
a). a two-digit number
b). a perfect square number
c), a number divisible by 5.
d). a number divisible by 2 or 3.
e). a number divisible by 2 and 3.
f). a number divisible by 7.
g). a number multiple of 8.
h). a two digit number divisible by 5.
i). a two digit number divisible by 2.
j). a two digit number divisible by 3.
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Answers
Answer:
Total possible outcomes=15
1.probability of picking a two digit number = individual no. All over tolal no.=2/30=15
2.the probability of picking a perfect square number...a number that is divisible by 2 i.e 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30. In total 15. Therefore the probability would be=15/30 giving u 2.
3.numbers divisible by 5 i.e 5,10,15,20,25,30. The probability=6/30=5
4.a number divisible by 2 or 3..=2,3,4,6,8,9,10,12,14,15,16,18,20,21,22,24,26,27,28,30 total =20.
Therefore the probability of a number divisible by 2 or 3=20/30= 2/3
5.numbers divisible by 7 are 7,14,21,28 total 4...
The probability will be 4/ 30=2/15.
6.two digit numbers divisible by 8 are 16,24total 2..the probability would be 2/30=15
7.two digit numbers divisible by 5 are 10,15,20,25,30 total 5. I.e the probability will be 5/30=6.
8.two digit numbers divisible by 2 are 10,12,14,16,18,20,22,24,26,28,30 total 11..i.e 11/30.
9.two digit numbers divisible by 3 are 12,18,21,24,27,30 total 6 i.e 6/30=5
Step-by-step explanation:
1. 2/30
2. 15/30
3. 6/30
4. 2/3
5. 2/15
6. 2/30
7. 5/30
8. 11/30
9. 6/30