Question

There are 4 flower beds each 5 meter by 4 meter at the corner of a square with grass paths 2 meter wide between them . find the total area of grass .If the whole is surrounded by a gravel path 3meter wide find the area of gravel path

Answer 1

Answer:

The rectangular ground is 40 m x 30 m. A 3 m wide path is parallel to the length and the width of the ground. What is the area of the path.

The area of the path = [40+30]*3 - 3*3 = 70*3–9 = 210–9 = 201 sq m.

Answer 2

Answer:

Area of grass = 40$m^{2}$

Area of gravel = 168$m^{2}$

Step-by-step explanation:

Area of one flowerbed = 5m x 4m = 20$m^{2}$

Width of the grass path = 2m

Side AB = CD of the plot = 4m + 2m + 4m = 10m

Side BC = AD of the plot = 5m + 2m + 5m = 12m

Area of the plot ABCD = 10m X 12m = 120$m^{2}$

Area of the grass = Area of the plot ABCD - Area of 4 flowerbeds

= 120$m^{2}$ - (4 X 20$m^{2}$)

= 120$m^{2}$ - 80$m^{2}$

= 40$m^{2}$

Width of the gravel path = 3m

Side PS = RQ of the plot = 10m (AB = CD) + 3m + 3m = 16m

Side RS = PQ of the plot = 12m (BC = AD) + 3m + 3m = 18m

Area of the plot PQRS = 16m X 18m = 288$m^{2}$

Area of the gravel path = Area of the plot PQRS - Area of the plot ABCD

= 288$m^{2}$ - 120$m^{2}$

= 168$m^{2}$