Question

There are 4 green, 3 red and 6 white marbles in a bag. A marble is picked at random. What is the probability of getting a non- green marble?

a) 6/13
b)9/13
c)4/13

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

There are 4 green, 3 red and 6 white marbles in a bag. A marble is picked at random. The probability of getting a non- green marble

$\displaystyle \sf{ a) \: \: \frac{6}{13} }$

$\displaystyle \sf{ b) \: \: \frac{9}{13} }$

$\displaystyle \sf{ c) \: \: \frac{4}{13} }$

EVALUATION

Here it is given that there are 4 green, 3 red and 6 white marbles in a bag

Total number of balls

= 4 + 3 + 6

= 13

So total number of possible outcomes = 13

Now a marble is picked at random

Let A be the event that of getting a non- green marble

The number of a non- green marbles

= 3 + 6

= 9

So total number of possible outcomes for the event A is 9

Hence the required probability

= P(A)

$\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}$

$\displaystyle \sf{ = \frac{9}{13} }$

FINAL ANSWER

Hence the correct option is

$\displaystyle \sf{ b) \: \: \frac{9}{13} }$

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