Question

There are 4 women p, q, r, s and 5 men v, w, x, y, z in a group. We are required to form pairs each consisting of one woman and one man. P is not to be paired with z, and y must necessarily be paired with someone. In how many ways can 4 such pairs be formed?

Answer 1

Answer:

$Total => 18+18+18+24=78$

Step-by-step explanation:

Hey Mate,

First Fix Y with Every Men P,Q,R,S now there wil be 4 case with each man  

1)P with Y for QRS => $4*3*2=24$

2)Q with Y for PRS => $3*3*2=18$

3)R with Y for PQS => $3*3*2=18$

4)S with Y for PQR => $3*3*2=18$

$Total => 18+18+18+24=78$

Note : P will not be with Z so 3