Question

there are 40 litres of pure milk in a vessel 16 litres of pure milk was taken out and replaced with equal amount of water again 10 litres of mixture was taken out and replaced with equal amount of water. what is the amount of water in the vessel now ? (in litres)

Answer 1

Part of mixture that is milk after 16 L is replaced =24/40
=3/5
And remaining milk =24L
Now, when 10 L mixture is removed, volume of milk removed = 3/5 of 10L
=6L
Now the remaining milk =24L-6L
=18L
Rest will be water. Therefore, amount of water =40L-18L
=22L [Answer]

Short Method:
Amount of milk remaining
=40{1-(16/40)}×{1-(10/40)} L
=40×(3/5)×(3/4) L
=18 L
Therefore, Water = 40L-18L
=22L [Answer]

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