Question

There are 40 passengers in a bus some with rupees 3 ticket and remaining with rupees 10 tickets the total collection from these passengers is rupees 295. find how many passengers have tickets worth rupees 3.​

Answer 1

Step-by-step explanation:

Total no. of passengers in the bus is = 40

Let the no. of passengers who have ₹ 3 tickets be x

Remaining passengers = 40 - x

A. T. Q

3x + 10 ( 40 - x ) = 295

3x + 400 - 10 x = 295

TRANSPORTING 295 TO LEFT HAND SIDE AND THEN

TRANSPORT 3x - 10x to RIGHT HAND SIDE

LIKE THIS

400-295 = 10x- 3x

and then solve this equation .....like this

400 - 295 = 10x- 3x

105 = 7x { TRANSPORTING 7 YO LEFT HAND SIDE }

105/7 = x { AFTER CUTTING }

15 = x

• THIS IS YOUR ANSWER