There are 45 boys and 54 girls in a class.determine the minimum number of chocolates required so that they can be distributed equally amOng girls or boys
Answers
The minimum number of chocolates distributed equally among girls or boys is 270.
Given,
There are 45 boys and 54 girls in the class.
To Find,
The minimum number of chocolates distributed.
Solution,
To find the minimum number of chocolates, we have to find the LCM of the number of boys and girls in the class.
Before finding the LCM let's understand the concept of the LCM.
LCM stands for Least Common Multiple and can be used to find the smallest common multiple between two or more numerical groups. Multiplying two or more numbers together yields a common multiple.
So, Let's find the LCM of 45 and 54.
LCM of 45 and 54
= 3 × 3 × 5 × 6.
= 270.
We can also find the LCM of the number using the prime factorization method.
So, Let's find the LCM of 45 and 54.
45 = 9 × 5.
54 = 9 × 6.
9 is common between the two numbers.
45 is a multiple of 5, and 54 is a multiple of 6.
So, the least common factors are 9,5, and 6.
LCM = 9×5×6
= 270.
The minimum number of chocolates distributed equally among girls or boys is 270.
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