Math, asked by tejachowdary78091, 11 months ago

There are 5 clients and 5 consultants in round table meeting. In how many ways can the clients be seated such that no consultant is next to the other consultant? (a) 5! 6! (b) 4! 4! (c) 4! 5! (d) 9! (e) 10c5 5! 4!

Answers

Answered by enyo
9

Answer: Therefore, option (b) is correct that there are 4! 4! ways the clients can be seated such that no consultant is next to the other.


Step-by-step explanation:

The formula for circular permutation= r!/r= (r-1)!

We use the above formula to calculate the number of ways 5 clients and 5 consultants can be seated such that no consultant is next to the other.

First, we place 5 consultants leaving one seat between them in round table meeting.

So, the number of ways of placing 5 consultants= (5-1)!

= 4!

Now, 5 places are left. Place the 5 clients on the left places.

So, the number of ways of placing 5 clients= (5-1)!

=4!

Therefore, total number of ways the clients can be seated is 4! 4! such that no consultant is next to the other.

Answered by rachurachana424
0

Answer:

it's is 4! 4! ways

Step-by-step explanation:

hope u have ur ans

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