Question

there are 5 consecutive integers in ascending order. the avg of the first and twice the last is equal to the avg of the other 3.find the 1st integer.

Answer 1

Let the 5 integers be x , x+1 , x+ 2 , x+3 , x+4 Now according to question{ x+ 2(x+4)}/2 = {x+1+x+2+x+3}/3=>3( 3x+8) = 2(3x+6) => 9x-6x = 12 -24 => 3x = -12 => x= -4 answer

Answer 2

the first integer is 4...........