Question

There are 5 distinct integers a, b, c, d, e in ascending order. (68-a)(68-b)(68-c)(68-d)(68-e) = 725.

Answer 1

"Since a, b, c, d and e are distinct integers, then (6-a), (6-b), (6-c), (6-d), and (6-e) must also be distinct integers, thus (6-a), (6-b), (6-c), (6-d), and (6-e) must be -1, 1, -3, 3, and 5.

(6-a) + (6-b) + (6-c) + (6-d) + (6-e) = 30- (a+b+c+d+e) = -1+1-3+3+5 = 5

a+b+c+d+e = 30 - 5 = 25."

Answer 2

Answer:

725 = -58-1*1*5*29

so we can write,

68-e = -5

=> e = 73

68-d = -1

=> d = 69

68-c = 1

=> c = 67

68 - b = 5

=> b = 63

68-a= 29

=> a = 39

so a+b+c+d = 39+63+67+69 = 238