Math, asked by Anonymous, 11 months ago

There are 5 girls
And 7 boys
A team of 3 boys and 2 girls is formed such that no 2 specific boys are in the same team . Find the number of ways to do so .

Answers

Answered by amitnrw
2

Answer:

200 Ways

Step-by-step explanation:

There are 5 girls

And 7 boys

A team of 3 boys and 2 girls is formed such that no 2 specific boys are in the same team . Find the number of ways to do so .

There are 7 boys

we can spilit boys into   5 boys & a group of two specific boys out of which only one can be selected in team

so we have 5 + 1  = 6  combination of boys

3 Boys can be selected = ⁶C₃

Total Girls = 5  &  2 girls can be selected as ⁵C₂

Total number of ways = ⁶C₃  * ⁵C₂

= 20 * 10

= 200

Answered by qwtiger
2

Answer:

According to the problem there are 5 girls and 7 boys

There are 7 boys.

we can divide those boys into 5 boys & a group of two specific boys among  which only one can be selected in team

therefore we have 5 + 1  

                        = 6  combination of boys

3 Boys can be selected as ⁶C₃

Total Girls = 5  

 2 girls can be selected as ⁵C₂

Total number of ways = ⁶C₃  * ⁵C₂

= 20 * 10

= 200

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