Question

:There are 5 green 7 red balls. Two balls are selected one by one without replacement. Find the probability that first is green and second is red

Answer 1

Probality=$\frac{number\:of\:outcomes}{number\:of\: favourable\:outcomes}$

P(of geting first is green ball)=$\frac{5}{12}$

p(of getting the second one is red)=$\frac{7}{12}$

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