Question

There are 5 women and 3 men applicants for a job.Only two out of eight are selected for a job.The probability that at least one of the selected person will be a women is:

Answer 1

Answer:

3/8

Step-by-step explanation:

as woman are 3 so the probability will be 3/8

Answer 2

Answer:

the probability of selecting at least one women is $\frac{25}{28}$

Step-by-step explanation:

given, number of men = 3

number of women = 5

total number of individuals = 8

2 people are selected, we have to find probability of at least one of them is a women

there are three outcomes

(i)  first is a woman and second man

(ii) first is a man and second woman

and (iii) both are women

for case (i),  probability is $\frac{5}{8}$ × $\frac{3}{7}$

for case (ii), probability is    $\frac{3}{8}$× $\frac{5}{7}$

case (iii), probability is $\frac{5}{8}$  × $\frac{4}{7}$

therefore , required probability =      $\frac{5}{8} .\frac{3}{7}$+ $\frac{3}{8} . \frac{5}{7}$  +$\frac{5}{8} . \frac{4}{7}$

        =  $\frac{15}{56}$ + $\frac{15}{56}$ +$\frac{20}{56}$

        = $\frac{50}{56}$ = $\frac{25}{28}$

hence, the probability of selecting at least one women is $\frac{25}{28}$