Question

there are 50 tickets numbered from 1 to 50 in a box. what is the probability of drawing a ticket bearing prime number​

Answer 1

Answer:

answer p(E) = 15/50 =3/10

so there 3/10 chances  of drawing  a ticket with a prime number on it

Step-by-step explanation:

( NOTE : because there are 15 prime numbers between 1 to 50 and later we have to divide it by 5 to get answer)

Answer 2

$Number \: of \: total \: possible \: outcomes \\= Number \: of \: tickets \\= 50 \: --(1)$

$Favourable \: outcomes \\= Prime \: numbers \: from \: 1\:to \: 50 \\= \{ 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47 \}$

$Number \: of \: favourable \: outcomes = 15 \:-(2)$

$\red{ Probability \: of \: drawing \: a\:ticket} \\\red{ bearing \: Prime \: number }\\= \frac{(2)}{(1)} \\= \frac{15}{50} \\= \frac{3}{10}$

Therefore.,

$\red{ Probability \: of \: drawing \: a\:ticket} \\\red{ bearing \: Prime \: number }\green {= \frac{3}{10}}$

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