Question

There are 500 children in a school. For a PmT show, they have to stand in such a manner that the number of rows is equal to the number of columns. How many children would be left out in this arrangment?

Answer 1

Hey mate..
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Given,

Total no. of children in a school = 500

Let, the no. of rows be x

And the no. of columns be y

A/Q,

x = y

i.e. x / y = 1....(1)

Also,

x + y = 500

=> x = 500 - y.......(2)

Putting the value of x in Eq.(1)..we have,

=> 500 - y / y = 1

=> 500 - y = y

=> 500 = 2y

=> 250 = y

Putting the value of y in Eq. (2) we get,

=> x = 500 - 250

=> x = 250

So,

We can see that the no. of students are equally distributed to both of the rows and columns .

Therefore , the no. of children left out in this arrangement is 0

Hope it helps...

Answer 2

Step-by-step explanation:

There are 16 students left out in this arrangement.