Question

there are 6.02×10²² moles each of N2,O2,and H2 which mixed together at 760mm and 273K the masMass o mixture in grams

Answer 1

Answer:

Explanation:

1Mol of each gas will contain 6.02*10^23 molecules

You have 6.02*10^22 molecules of each gas

You have (6.02*10^22) / (6.02*10^23) = 0.1 mol of each gas

Molar mass N2 = 28g/mol

Mass of 0.1 mol N2 = 0.1*28 = 2.8g

Molar mass O2 = 32g/mol

Mass of 0.1 mol O2 = 0.1*32 = 3.2g

Molar mass H2 = 2g/mol

Mass of 0.1 mol = 0.1*2 = 0.2g

Total mass = 2.8+3.2+0.2 = 6.02g - Choice a) is correct.

Note: when dealing with moles and masses of gas , the pressure and temperature conditions are not necessary.