Math, asked by yashtomaryt300, 9 months ago

There are 60 lemons a man sold 30 for rs 1 for 2 lemon and another for rs 1 for 3 lemons when both came a man rs 15 for 30 lemon and another man got rs 10 ruppes for 30 lenons so total money was rs 25 now another day another man got unwell so he told a man to sell his lemons another man gave ther rs for selling the same rs he usually sells rs 1 for 3 lemons and a man sells rs 1 for 2 lemons so he sold lemons of rs 2 for 5 lemons(1 +1 =2+3) mens rs 2 is 5 lemons after selling his total was rs 24 for 60 lemons and earlier it was 25 for 60 lemons if the rate price and value are same then where did 1 ruppes go.​

Answers

Answered by kotalrsarvani
16

Step-by-step explanation:

Suppose Tom and Harry have 30 lemons each. Tom sells at the rate of 3 lemons for Rs. 1 and Harry sells at the rate of 2 lemons for Rs. 1. So in the end Tom earns 30 / 3 * 1= 10 Rupees and Harry earns 30 / 2 * 1 = 15 Rupees. So total of 10 + 15 = 25 Rs for 30 + 30 = 60 lemons.

One day Tom leaves out leaving all lemons to Harry. So Harry sells 3 + 2 = 5 lemons for 1 + 1 = 2 rupees. So in the end Harry sells 60/5 * 2 = 12 * 2 = 24 rupees.

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