Question

There are 650 candidates from five different states to participate in a competition from state 1 the number of candidates is 12% of the total candidates. From state 2 the other one fifth of the total candidates. There are 8% of total candidates from state 3. The number of candidates from state 4 and state 5 is equal.
(i) How many candidates participated from state 4?
(ii) what is the ratio between the number of candidates from state 2 and state 3?​

Answer 1

Answer:

I) 290

ii) 5:1

Step-by-step explanation:

Given,

Total number of candidates =650

number of candidates from state 1= 12/100 * 650= 78

number of candidates from state 2= 1/5 * 650=130

number of candidates from state 3= 8/100 * 650=62

Let the number of candidates from state 4 and 5 be x.

I) Therefore,

78+130+62+x+x = 650

270 + 2x = 650

2x = 650-270

x= 380/2

x= 290

So, the number of participants from state 4 is 290

ii) Ratio between the numbers of candidates from state 2 and 3=130/62=5/1 =5:1